Show that a - b 2 a2 + b2 a + b2 are in a.p
WebFeb 18, 2024 · Answer: a^3-b^3. Step-by-step explanation: (a−b)(a2+ab+b2) =(a+−b)(a2+ab+b2) =(a)(a2)+(a)(ab)+(a)(b2)+(−b)(a2)+(−b)(ab)+(−b)(b2) =a3+a2b+ab2−a2b−ab2−b3 WebIf A happens, it excludes B from happening, and vice-versa. A B Ω If Aand B are mutually exclusive, P(A∪B) = P(A)+ P(B). For all other Aand B, P(A∪B) = P(A)+ P(B)−P(A∩B). Definition: Any number of events B1,B2,...,B kare mutually exclusive if every pair of the events is mutually exclusive: ie. B i∩B j= ∅for alli,jwithi6= j. Ω B1B2B3
Show that a - b 2 a2 + b2 a + b2 are in a.p
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WebX, Y, A, B are the most commonly used letters that represent algebraic problems and equations. Important Formulas in Algebra Here is a list of Algebraic formulas – a 2 – b 2 = (a – b) (a + b) (a + b) 2 = a 2 + 2ab + b 2 a 2 + b 2 = (a + b) 2 – 2ab (a – b) 2 = a 2 – 2ab + b 2 (a + b + c) 2 = a 2 + b 2 + c 2 + 2ab + 2bc + 2ca Web(A + A-1)2 = AP + A-2 B. AB = BA C. A + B is invertible D. (A + B)2 A2 + B2 + 2AB E. 4A is invertible F. (In - A)(In + A) = In - A2 = Show transcribed image text. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the quality high.
WebHere, we are given three terms and we need to show that they are in A.P., First-term ( a 1) = ( a - b) 2 Second term ( a 2) = ( a 2 + b 2) Third term ( a 3) = ( a + b) 2 So in an A.P, the …
WebSimplify (a+b)(a^2-ab+b^2) Step 1. Expand by multiplying each term in the first expression by each term in the second expression. Step 2. Simplify terms. Tap for more steps... Step … WebAlgebra Simplify (a+b) (a^2-ab+b^2) (a + b) (a2 − ab + b2) ( a + b) ( a 2 - a b + b 2) Expand (a+b)(a2 −ab+b2) ( a + b) ( a 2 - a b + b 2) by multiplying each term in the first expression by each term in the second expression. a⋅a2 + a(−ab)+ab2 +ba2 +b(−ab)+b⋅b2 a ⋅ a 2 + a ( - a b) + a b 2 + b a 2 + b ( - a b) + b ⋅ b 2 Simplify terms.
WebBy squaring $1=ax+by$ both sides, I get, $1=(ax)^2+2(ax)(by)+(by)^2$, but this doesn't help my proof. Stack Exchange Network Stack Exchange network consists of 181 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Web(a) Let P(B1∩B2)>0, and A1∪A2⊂B1∩B2. Then show that. P(A1 B1).P(A2 B2)=P(A1 B2).P(A2 B1). (b) Let A and B1 be independent; similarly, let A and B2 be independent. Show that in this case, A and B1∪B2 are independent if and only if A and B1∩B2 are independent. (c) Given P(A) = 0.42,P(B) = 0.25, and P(A∩B) = 0.17, find … character cocking a handgun front viewWebSo, Area of square of length (a+b) = (a+b) 2 = (i) + (ii) + (iii) + (iv) Therefore : (a+b) 2 = a 2 + ba + ba +b 2. i.e. (a+b)2 = a2 + 2ab + b2. Hence Proved. This simple formula is also used … character coat of armsWebBest answer The given numbers are (a-b)2, (a2 +b2) and (a2 +b2). Since each term differs from its preceding term by a constant, therefore, the given numbers are in AP. ← Prev … character coats for boysWebIf a, b, c and d are in G.P. show that (a 2+b 2+c 2)(b 2+c 2+d 2)=(ab+bc+cd) 2 Hard Solution Verified by Toppr Taking LHS (a 2+b 2+c 2)(b 2+c 2+d 2) putting values b=ar,c=ar 2,d=ar 3 (a 2+(ar) 2+(ar 2) 2)((ar) 2+(ar 2) 2+(ar 3) 2) =a 2(1+r 2+r 4)a 2(r 2+r 4+r 6) =a 4r 2(1+r 2+r 4) 2 RHS =(ab+bc+cd) 2 =(a×ar+ar×ar 2+ar 2×ar 3) 2 character code checklist excelWebJun 10, 2024 · Show that (a - b)2, (a2 +b2) and (a + b)2 are in Ap See answer Advertisement Suchetsadekar The resulting series is an A.P. with common difference = 2ab are u sure about this solution Advertisement Advertisement character code for arrow in wordWebThe a 2 - b 2 formula is given as: a 2 - b 2 = (a - b) (a + b). If you would like to verify this, you can just multiply (a - b) and (a + b) and see whether you get a 2 - b 2. Verification of a 2 - b 2 Formula. Let us see the proof of a square minus b square formula. To verify that a 2 - b 2 = (a - b) (a + b) we need to prove LHS = RHS. Let us ... character code for asteriskWebMedium Solution Verified by Toppr Correct option is A) Given, 2a 2+2b 2=a 2+2ab+b 2. We know, (a+b) 2=a 2+2ab+b 2 and (a−b) 2=a 2−2ab+b 2. The value of 2(a 2+b 2)=(a+b) 2 is … character code checklist word